What is the derivative of 5-4/x ?

The derivative of 5-4/x is 4/(x^2)

What is the first derivative of 5-4/x ?

The first derivative of 5-4/x is 4/(x^2)

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\frac{d}{d x} (5 - \frac{4}{x})

\frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (5 - \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5) - \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (5) = 0

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 0 - (- \frac{4}{x ^{2}})

Simplify

= \frac{4}{x ^{2}}

\frac{- u ^{2} + 7}{( u ^{2} + 7 ) ^{2}}

\frac{d}{d x} (sec (x^{5} + x))

(1.1) (0.5)

\int 1 + 5 x^{2} (10 x) d x

y = 3 x^{2} + \frac{10 x}{3} - 2

What is the derivative of 5-4/x ?
The derivative of 5-4/x is 4/(x^2)
What is the first derivative of 5-4/x ?
The first derivative of 5-4/x is 4/(x^2)