integral from 1 to sqrt(2 of)x

Lösung

\int_{1}^{2} x d x

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{1}^{2} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{1}^{2}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{2}

\frac{\partial}{\partial z} (arctan (\frac{y}{x}))

\int \frac{x ^{2} - x + 10}{( x + 2 ) ( x ^{2} + 4 )} d x

\frac{\partial}{\partial x} (2 x^{3} + x^{2} y^{3} - 3 y^{2})

n = 0 \sum \infty 3 (- 0.1)^{n}

\int arctan (u) d u