derivative y= 5/7 x+4/3

Lösung

ableitung von

y = \frac{5}{7} x + \frac{4}{3}

\frac{5}{7}

Dezimale

0.71428 \dots

Schritte zur Lösung

\frac{d}{d x} (\frac{5}{7} x + \frac{4}{3})

Vereinfache

\frac{5}{7} x + \frac{4}{3} : \frac{5 x}{7} + \frac{4}{3}

= \frac{d}{d x} (\frac{5 x}{7} + \frac{4}{3})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{5 x}{7}) + \frac{d}{d x} (\frac{4}{3})

\frac{d}{d x} (\frac{5 x}{7}) = \frac{5}{7}

\frac{d}{d x} (\frac{4}{3}) = 0

= \frac{5}{7} + 0

Vereinfache

= \frac{5}{7}

y^{^{''}} + 2 y = 3, y (0) = - 1, y^{^{'}} (0) = 2

\frac{d}{d x} (lo g_{5} (2 x^{3} + x^{2}))

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 8 x - y}

\frac{\partial}{\partial x} ((5 y^{4}) cos (5 x))

d er i v a t i v e h (t) = (t + 2)^{\frac{2}{3}} (2 t^{2} - 3)^{3}