What is (\partial)/(\partial x)(-1/x) ?

The answer to (\partial)/(\partial x)(-1/x) is 1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-1/x)

\frac{\partial}{\partial x} (- \frac{1}{x})

\frac{1}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (- \frac{1}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - (- 1 \cdot x^{- 1 - 1})

Simplify

- (- 1 \cdot x^{- 1 - 1}) : \frac{1}{x ^{2}}

= \frac{1}{x ^{2}}

\int e^{x} cos (3 x) d x

n = 1 \sum \infty 5^{n} x^{n} n!

\frac{d}{d x} (7 e^{2 x^{4} - 3 x})

\int 4 t^{5} d t

\frac{8}{( 9 s ^{2} + 9 s + 4 ) ( s )}

What is (\partial)/(\partial x)(-1/x) ?
The answer to (\partial)/(\partial x)(-1/x) is 1/(x^2)