What is the integral of x*sqrt(1-x^2) ?

The integral of x*sqrt(1-x^2) is -1/3 (1-x^2)^{3/2}+C

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integral of x*sqrt(1-x^2)

\int x \cdot 1 - x^{2} d x

- \frac{1}{3} (1 - x^{2})^{\frac{3}{2}} + C

Solution steps

\int x 1 - x^{2} d x

Apply u-substitution

: \int - u^{2} d u

= \int - u^{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= - \frac{u ^{3}}{3}

Substitute back

u = 1 - x^{2}

= - \frac{( 1 - x ^{2} ) ^{3}}{3}

Simplify

- \frac{( 1 - x ^{2} ) ^{3}}{3} : - \frac{1}{3} (1 - x^{2})^{\frac{3}{2}}

= - \frac{1}{3} (1 - x^{2})^{\frac{3}{2}}

Add a constant to the solution

= - \frac{1}{3} (1 - x^{2})^{\frac{3}{2}} + C

f (x) = 2 x^{2} - 3 x + 6

f (x) = lo g_{2} (x^{2} + 1) - 2^{3}

\frac{\partial}{\partial x} (y + 3)

\int p (p + 6)^{8} d p

\frac{d}{d x} (\frac{0.2 x}{x ^{2} + 9})

What is the integral of x*sqrt(1-x^2) ?
The integral of x*sqrt(1-x^2) is -1/3 (1-x^2)^{3/2}+C