What is the tangent of f(x)=7e^{0.03x},\at x=9 ?

The tangent of f(x)=7e^{0.03x},\at x=9 is y=0.27509…x+7e^{0.27}-2.47583…

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tangent of f(x)=7e^{0.03x},\at x=9

tangent of

f (x) = 7 e^{0.03 x}, at x = 9

y = 0.27509 \dots x + 7 e^{0.27} - 2.47583 \dots

Solution steps

Find the tangent point:

(9, 7 e^{0.27})

Find the slope of

f (x) = 7 e^{0.03 x} : \frac{df ( x )}{d x} = 0.21 e^{0.03 x}

Compute the slope of

f (x) = 7 e^{0.03 x}

x = 9 : m = 0.27509 \dots

Find the line with slope m=

0.27509 \dots

and passing through

(9, 7 e^{0.27}) : y = 0.27509 \dots x + 7 e^{0.27} - 2.47583 \dots

y = 0.27509 \dots x + 7 e^{0.27} - 2.47583 \dots

3 sin (x), 8 cos (x)

x \to 2 lim ((1 + x)^{\frac{1}{x}})

\int \frac{( 1 - x ^{2} )}{x ^{2}} d x

\int - 9 d x

\frac{d}{d x} (\frac{1}{( 3 - x ) ^{4}})

What is the tangent of f(x)=7e^{0.03x},\at x=9 ?
The tangent of f(x)=7e^{0.03x},\at x=9 is y=0.27509…x+7e^{0.27}-2.47583…