2tx^{''}-x^'+1/((x^'))=0

Lösung

2 t x^{^{''}} - x^{^{'}} + \frac{1}{( x ^{^{'}} )} = 0

x = \frac{2 ( c _{1} t + 1 ) ^{\frac{3}{2}}}{3 c _{1}} + c_{2}, x = - \frac{2 ( c _{1} t + 1 ) ^{\frac{3}{2}}}{3 c _{1}} + c_{2}

Schritte zur Lösung

2 t x^{''} (t) - x^{'} (t) + \frac{1}{( x ^{'} ( t ) )} = 0

Solve using substitution:

x = \frac{2 ( c _{1} t + 1 ) ^{\frac{3}{2}}}{3 c _{1}} + c_{2}, x = - \frac{2 ( c _{1} t + 1 ) ^{\frac{3}{2}}}{3 c _{1}} + c_{2}

x = \frac{2 ( c _{1} t + 1 ) ^{\frac{3}{2}}}{3 c _{1}} + c_{2}, x = - \frac{2 ( c _{1} t + 1 ) ^{\frac{3}{2}}}{3 c _{1}} + c_{2}

\int \frac{( x ^{3} )}{x ^{2} + 16} d x

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d er i v a t i v e f (x) = - 2 x^{3}