derivative h(x)= 1/(x^2)+1/x+x

Lösung

ableitung von

h (x) = \frac{1}{x ^{2}} + \frac{1}{x} + x

- \frac{2}{x ^{3}} - \frac{1}{x ^{2}} + 1

Schritte zur Lösung

\frac{d}{d x} (\frac{1}{x ^{2}} + \frac{1}{x} + x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x ^{2}}) + \frac{d}{d x} (\frac{1}{x}) + \frac{d x}{d x}

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d x}{d x} = 1

= - \frac{2}{x ^{3}} - \frac{1}{x ^{2}} + 1

\int \frac{cos ( a x )}{b - a sin ( a x )} d x

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\frac{d}{d x} (arcsin (\frac{x}{1 - x}))

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\int \frac{sin ( x + 1 )}{x + 1} d x