derivative ((sqrt(x)))/(x+1)

Lösung

ableitung von

\frac{( x )}{x + 1}

\frac{- x + 1}{2 x ( x + 1 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x}{x + 1})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x}{( x + 1 ) ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (x + 1) = 1

= \frac{\frac{1}{2 x} ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}}

Vereinfache

\frac{\frac{1}{2 x} ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}} : \frac{- x + 1}{2 x ( x + 1 ) ^{2}}

= \frac{- x + 1}{2 x ( x + 1 ) ^{2}}

\int \frac{x}{x ^{4} + 8 x ^{2} + 17} d x

\frac{\partial}{\partial x} (y cos (x))

\int_{5}^{e^{3}} \frac{1}{x} d x

y^{^{'}} = x e^{y}

\frac{\partial}{\partial y} (sin^{2} (y))