2r(s^2+1)dr+(r^4+1)ds=0

Lösung

2 r (s^{2} + 1) d r + (r^{4} + 1) d s = 0

s = tan (- arctan (r^{2}) + c_{1})

Schritte zur Lösung

2 r (s^{2} + 1) d r + (r^{4} + 1) d s = 0

Solve separable ODE:

s = tan (- arctan (r^{2}) + c_{1})

s = tan (- arctan (r^{2}) + c_{1})

\int_{- \infty}^{15} x e^{\frac{x}{5}} d x

x \to 1 lim (\frac{1}{x ^{2} - x})

t an g e n t 18 cos (2 x) - sin (x)

\int_{1}^{2} 7 r^{4} ln (r) d r

\int \frac{1}{x ^{2} + 2 x + 7} d x