fläche y=-x,y=sqrt(2-x),y=0

Lösung

fläche

y = - x, y = 2 - x, y = 0

\frac{10}{3}

Dezimale

3.33333 \dots

Schritte zur Lösung

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

- x = 2 - x : x = - 2

- x = 0 : x = 0

2 - x = 0 : x = 2

= \int_{- 2}^{0} ∣ f_{1} (x) - f_{2} (x) ∣ d x + \int_{0}^{2} ∣ f_{2} (x) - f_{3} (x) ∣ d x

= \int_{- 2}^{0} - x - 2 - x d x + \int_{0}^{2} 2 - x - 0 d x

\int_{- 2}^{0} - x - 2 - x d x = - 2 + \frac{16 - 4 2}{3}

\int_{0}^{2} 2 - x - 0 d x = \frac{4 2}{3}

= - 2 + \frac{16 - 4 2}{3} + \frac{4 2}{3}

Vereinfache

= \frac{10}{3}

d er i v a t i v e y = \frac{3 x ^{2}}{2 x + 4}

\frac{\partial}{\partial x} (2 A y (L - x))

\int sec^{2} (7 - 4 x) d x

\int (9 x^{2} + 6 x) d x

d er i v a t i v e y = 3 t + 2 t^{3}