y^{''}+y=(cot(x))^2

Lösung

y^{^{''}} + y = (cot (x))^{2}

y = c_{1} cos (x) + c_{2} sin (x) + (- ln (tan (\frac{x}{2})) - cos (x)) cos (x) + (- csc (x) - sin (x)) sin (x)

Schritte zur Lösung

y^{''} (x) + y = (cot (x))^{2}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + (- ln (tan (\frac{x}{2})) - cos (x)) cos (x) + (- csc (x) - sin (x)) sin (x)

y = c_{1} cos (x) + c_{2} sin (x) + (- ln (tan (\frac{x}{2})) - cos (x)) cos (x) + (- csc (x) - sin (x)) sin (x)

\frac{\partial}{\partial x} (\frac{6 x}{x ^{2} + 5})

\int 4 ln (x) d x

\frac{\partial}{\partial x} (x^{7} y^{8} + 3 x^{5} y)

n = 0 \sum \infty \frac{2 n}{n + 3}

x \frac{d y}{d x} + y = - 5 x y^{2}