(\partial)/(\partial x)(cos(2x-3y^2))

解

\frac{\partial}{\partial x} (cos (2 x - 3 y^{2}))

- sin (2 x - 3 y^{2}) \cdot 2

解答ステップ

\frac{\partial}{\partial x} (cos (2 x - 3 y^{2}))

y

を定数として扱う

連鎖法則を適用:

- sin (2 x - 3 y^{2}) \frac{\partial}{\partial x} (2 x - 3 y^{2})

= - sin (2 x - 3 y^{2}) \frac{\partial}{\partial x} (2 x - 3 y^{2})

\frac{\partial}{\partial x} (2 x - 3 y^{2}) = 2

= - sin (2 x - 3 y^{2}) \cdot 2