derivative of 2xe^x-e^{2x}

Lösung

\frac{d}{d x} (2 x e^{x} - e^{2 x})

2 (e^{x} + e^{x} x) - e^{2 x} \cdot 2

Schritte zur Lösung

\frac{d}{d x} (2 x e^{x} - e^{2 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x e^{x}) - \frac{d}{d x} (e^{2 x})

\frac{d}{d x} (2 x e^{x}) = 2 (e^{x} + e^{x} x)

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= 2 (e^{x} + e^{x} x) - e^{2 x} \cdot 2

\frac{d}{d x} ((2 x^{3} + 2) (x^{4} - 3 x))

t an g e n t f (x) = \frac{x}{1 + x ^{2}}, (3, 0.3)

in v erse l a pl a ce \frac{( 1 )}{( s - 3 ) ( s + 1 )}

\int \frac{25 x ^{2} - 1}{x} d x

\int 2 (x + 20) e^{\frac{x}{20}} d x