integral of (10-5x)

解答

\int (10 - 5 x) d x

10 x - \frac{5 x ^{2}}{2} + C

求解步骤

\int 10 - 5 x d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 d x - \int 5 x d x

\int 10 d x = 10 x

\int 5 x d x = \frac{5 x ^{2}}{2}

= 10 x - \frac{5 x ^{2}}{2}

解答补常数

= 10 x - \frac{5 x ^{2}}{2} + C

x^{2} y^{^{''}} + 3 x y^{^{'}} + 5 y = 0

\frac{\partial}{\partial y} (x e^{x^{3}})

d er i v a t i v e y = 2 x - 1

\int \frac{5 x}{( x - 2 ) ^{2}} d x

\frac{d}{d θ} (tan (\frac{θ}{2}))