derivative of x-0.8-0.2sin(x)

Lösung

\frac{d}{d x} (x - 0.8 - 0.2 sin (x))

- 0.2 cos (x) + 1

Schritte zur Lösung

\frac{d}{d x} (x - 0.8 - 0.2 sin (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (0.8) - \frac{d}{d x} (0.2 sin (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (0.8) = 0

\frac{d}{d x} (0.2 sin (x)) = 0.2 cos (x)

= 1 - 0 - 0.2 cos (x)

Vereinfache

= - 0.2 cos (x) + 1

8 cos^{2} (y) d x + csc^{2} (x) d y = 0, y (\frac{π}{12}) = \frac{π}{4}

\frac{d}{d x} (\frac{a + b x + c x ^{2}}{x})

\frac{d y}{d x} + 4 y = e^{- 4 x}

\frac{\partial}{\partial x} (3 x^{2} - 3)

\int \frac{x - 1}{x ^{2} ( x + 1 ) ^{2}} d x