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Beliebt Rechnen >

(ln(t^2+1))^'

Lösung

(ln (t^{2} + 1))^{^{'}}

Lösung

\frac{2 t}{t ^{2} + 1}

Schritte zur Lösung

(ln (t^{2} + 1))^{'}

Wende die Kettenregel an:

\frac{1}{t ^{2} + 1} (t^{2} + 1)^{'}

= \frac{1}{t ^{2} + 1} (t^{2} + 1)^{'}

(t^{2} + 1)^{'} = 2 t

= \frac{1}{t ^{2} + 1} \cdot 2 t

Vereinfache

\frac{1}{t ^{2} + 1} \cdot 2 t : \frac{2 t}{t ^{2} + 1}

= \frac{2 t}{t ^{2} + 1}

Graph

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