derivative y=-3x-2

Lösung

ableitung von

y = - 3 x - 2

- 3

Schritte zur Lösung

\frac{d}{d x} (- 3 x - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= - 3 - 0

Vereinfache

= - 3

x^{^{''}} + 6 x^{^{'}} + 7 x = 0, x (0) = 0, x^{^{'}} (0) = 1

\int_{2}^{5} (4 x - 2) d x

(x)^{^{'}}

\int \frac{180 x ^{2}}{( 3 x + 1 ) ( 3 x + 5 ) ( x + 2 )} d x

f (x) = cos (ln (x))