integral of (x^3+1)^3

Lösung

\int (x^{3} + 1)^{3} d x

\frac{x ^{10}}{10} + \frac{3 x ^{7}}{7} + \frac{3 x ^{4}}{4} + x + C

Schritte zur Lösung

\int (x^{3} + 1)^{3} d x

Multipliziere aus

(x^{3} + 1)^{3} : x^{9} + 3 x^{6} + 3 x^{3} + 1

= \int x^{9} + 3 x^{6} + 3 x^{3} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{9} d x + \int 3 x^{6} d x + \int 3 x^{3} d x + \int 1 d x

\int x^{9} d x = \frac{x ^{10}}{10}

\int 3 x^{6} d x = \frac{3 x ^{7}}{7}

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int 1 d x = x

= \frac{x ^{10}}{10} + \frac{3 x ^{7}}{7} + \frac{3 x ^{4}}{4} + x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{10}}{10} + \frac{3 x ^{7}}{7} + \frac{3 x ^{4}}{4} + x + C

t an g e n t f (x) = x^{2} - 2 x + 1

x \to \infty lim ((x)^{2})

x \to 0 lim (\frac{x}{2})

\int 5 x^{2} (2 x^{3} + 3)^{4} d x

\int \frac{( ln ( ln ( x ) ) )}{x} d x