laplacetransform 8sin(t)

Lösung

laplace transformation

8 sin (t)

\frac{8}{s ^{2} + 1}

Schritte zur Lösung

L {8 sin (t)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 8 L {sin (t)}

L {sin (t)} : \frac{1}{s ^{2} + 1}

= 8 \cdot \frac{1}{s ^{2} + 1}

Fasse

8 \frac{1}{s ^{2} + 1}

zusammen:

\frac{8}{s ^{2} + 1}

= \frac{8}{s ^{2} + 1}

k = 1 \sum \infty \frac{k ^{3}}{5 ^{k}}

\int \frac{7 sin ( x ) + 2 sec ( x )}{tan ( x )} d x

in v erse l a pl a ce \frac{s}{2 s + 4}

\frac{\partial}{\partial x} (\frac{5}{x y} + \frac{x}{y} + \frac{y}{x})

\frac{d}{d x} (x^{3} + x^{2} - 5 x)