derivative g(x)= 2/(x^3)-1/(x^2)

Lösung

ableitung von

g (x) = \frac{2}{x ^{3}} - \frac{1}{x ^{2}}

- \frac{6}{x ^{4}} + \frac{2}{x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (\frac{2}{x ^{3}} - \frac{1}{x ^{2}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x ^{3}}) - \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= - \frac{6}{x ^{4}} - (- \frac{2}{x ^{3}})

Vereinfache

= - \frac{6}{x ^{4}} + \frac{2}{x ^{3}}

\frac{d y}{d x} = x + x y^{2}

d er i v a t i v e f (x) = x^{3 x}

(t + 2 y + 3) + (2 t + 4 y - 1) \frac{d y}{d t} = 0

y^{^{''}} - \frac{1}{x} y^{^{'}} + \frac{1}{x ^{2}} y = \frac{2}{x}

\frac{d}{d t} (5 t^{2})