(dy)/(dx)=(y+1)(y-2),y(0)=0

Lösung

\frac{d y}{d x} = (y + 1) (y - 2), y (0) = 0

y^{2} - y - 2

Schritte zur Lösung

Finde

(y + 1) (y - 2)

gegeben

y (0) = 0

(y + 1) (y - 2) = (y + 1) (y - 2)

y : 0

y : 0

= (y + 1) (y - 2)

Multipliziere aus

(y + 1) (y - 2) : y^{2} - y - 2

= y^{2} - y - 2

\frac{\partial}{\partial x} (6 ln (6 x^{3} + y^{2}))

d er i v a t i v e g (t) = t^{3} cos (t)

\frac{d}{d x} (ln (2 x^{2} - 1))

x \to - 0.00000001 lim (x^{x})

d er i v a t i v e f (x) = [x + (x + sin^{2} (x))^{3}]^{4}