We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-4y^'+5y=1+t,y(0)=0,y^'(0)=4 ?
- The solution for y^{''}-4y^'+5y=1+t,y(0)=0,y^'(0)=4 is y=e^{2t}(-9/25 cos(t)+113/25 sin(t))+t/5+9/25