y^'-2y^{'''}+y^{''}=0

Lösung

y^{^{'}} - 2 y^{^{'''}} + y^{^{''}} = 0

y = c_{1} + c_{2} e^{- \frac{t}{2}} + c_{3} e^{t}

Schritte zur Lösung

y^{'} (t) - 2 y^{'''} (t) + y^{''} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{t}{2}} + c_{3} e^{t}

y = c_{1} + c_{2} e^{- \frac{t}{2}} + c_{3} e^{t}

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = - 1

\frac{d ^{2} x}{d t ^{2}} + 0.75 \frac{d x}{d t} + 0.3 x = 0

y^{^{''}} + 10 y^{^{'}} + 2 y = 0

x^{^{''}} + 5 x^{^{'}} + 3 x = 0, x (0) = 5, x^{^{'}} (0) = 7

y^{^{''}} - 22 y^{^{'}} + 121 y = 0, y (0) = 0, y^{^{'}} (0) = 5