2y^{''}+12y^'+18y=0

Lösung

2 y^{^{''}} + 12 y^{^{'}} + 18 y = 0

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t}

Schritte zur Lösung

2 y^{''} (t) + 12 y^{'} (t) + 18 y = 0

Solve linear ODE:

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t}

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t}

y^{^{''}} + 2 y^{^{'}} + 9 y = 0, y (0) = 1, y^{^{'}} (0) = 0

3 x^{^{''}} - 7 x^{^{'}} + 4 x = 0

y^{^{''}} + 4 y^{^{'}} - 5 y = 0, y (ln (2)) = 3, y (0) = 33

y^{^{'''}} - 5 y^{^{''}} + 5 y^{^{'}} + 11 y = 0

36 y^{^{''}} + 108 y^{^{'}} + 97 y = 0, y^{^{'}} (1) = 3, y (1) = 4