derivative sin(x)ln(sec(x)+tan(x))-1

解答

导数

sin (x) ln (sec (x) + tan (x)) - 1

cos (x) ln (sec (x) + tan (x)) + tan (x)

求解步骤

\frac{d}{d x} (sin (x) ln (sec (x) + tan (x)) - 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x) ln (sec (x) + tan (x))) - \frac{d}{d x} (1)

\frac{d}{d x} (sin (x) ln (sec (x) + tan (x))) = cos (x) ln (sec (x) + tan (x)) + tan (x)

\frac{d}{d x} (1) = 0

= cos (x) ln (sec (x) + tan (x)) + tan (x) - 0

化简

= cos (x) ln (sec (x) + tan (x)) + tan (x)

x \to 6 lim (\frac{x ^{2} - 5}{x - 6})

d er i v a t i v e f (x) = x^{2} 3 x + 5

d er i v a t i v e cos (a^{4} + x^{4})

n = 0 \sum \infty (- 1)^{n} \frac{( ln ( 2 ) ) ^{n}}{n !}

a re a 12 - x^{2}, x^{2} - 6, - 3, 3