de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^{''}-2y^'+y=e^{t-1},y(1)=0,y^'(1)=5

Lösung

y^{^{''}} - 2 y^{^{'}} + y = e^{t - 1}, y (1) = 0, y^{^{'}} (1) = 5

Lösung

y = - \frac{9 e ^{t - 1}}{2} + 4 e^{t - 1} t + \frac{e ^{t - 1} t ^{2}}{2}

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + y = e^{t - 1}

Solve linear ODE:

y = - \frac{9 e ^{t - 1}}{2} + 4 e^{t - 1} t + \frac{e ^{t - 1} t ^{2}}{2}

y = - \frac{9 e ^{t - 1}}{2} + 4 e^{t - 1} t + \frac{e ^{t - 1} t ^{2}}{2}

Graph

Beliebte Beispiele

y^{''}-y^'=xe^{2x}

y^{^{''}} - y^{^{'}} = x e^{2 x}

y^{''}+4y=-8sin(2t)

y^{^{''}} + 4 y = - 8 sin (2 t)

y^{''}-2y^'+2y=e^2x(cos(x)-9sin(x))

y^{^{''}} - 2 y^{^{'}} + 2 y = e^{2} x (cos (x) - 9 sin (x))

(d^2y)/(dt^2)-2(dy)/(dt)+y=5e^t

\frac{d ^{2} y}{d t ^{2}} - 2 \frac{d y}{d t} + y = 5 e^{t}

y^{''}-xe^{-x}=2y^'

y^{^{''}} - x e^{- x} = 2 y^{^{'}}