y^{''}+y=tan(x)+x

Lösung

y^{^{''}} + y = tan (x) + x

y = c_{1} cos (x) + c_{2} sin (x) + cos (x) (x cos (x) - ln (tan (x) + sec (x))) + x sin^{2} (x)

Schritte zur Lösung

y^{''} (x) + y = tan (x) + x

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + cos (x) (x cos (x) - ln (tan (x) + sec (x))) + x sin^{2} (x)

y = c_{1} cos (x) + c_{2} sin (x) + cos (x) (x cos (x) - ln (tan (x) + sec (x))) + x sin^{2} (x)

y^{^{''}} = - 0.1 y^{^{'}} - x

y^{^{''}} + 4 y = g (t)

y^{^{''}} - 3 y^{^{'}} = 2 x - 3

y^{^{'''}} - 6 y^{^{''}} + 8 y^{^{'}} = sin (2 t) + t^{2} e^{t}

y^{^{''}} - 6 y^{^{'}} + 9 y = 15 x + 4