4y^{''}+y=4cos(x)

Lösung

4 y^{^{''}} + y = 4 cos (x)

y = c_{1} cos (\frac{x}{2}) + c_{2} sin (\frac{x}{2}) - \frac{4}{3} cos (x)

Schritte zur Lösung

4 y^{''} (x) + y = 4 cos (x)

Solve linear ODE:

y = c_{1} cos (\frac{x}{2}) + c_{2} sin (\frac{x}{2}) - \frac{4}{3} cos (x)

y = c_{1} cos (\frac{x}{2}) + c_{2} sin (\frac{x}{2}) - \frac{4}{3} cos (x)

y^{^{''}} + 2 y^{^{'}} + 2 y = e^{x} sin (x)

y^{^{''}} - 4 y^{^{'}} = 4 x

y^{^{''}} - 5 y^{^{'}} + 7 y = x e^{x}

y^{^{'''}} + y^{^{'}} = cos (x)

y^{^{''}} + 6 y^{^{'}} = 1 - 3 x + x^{2}