y^{''}+49y=17sec^2(7t)

Lösung

y^{^{''}} + 49 y = 17 sec^{2} (7 t)

y = c_{1} cos (7 t) + c_{2} sin (7 t) + \frac{- 17 + 17 ln ( tan ( 7 t ) + sec ( 7 t ) ) sin ( 7 t )}{49}

Schritte zur Lösung

y^{''} (t) + 49 y = 17 sec^{2} (7 t)

Solve linear ODE:

y = c_{1} cos (7 t) + c_{2} sin (7 t) + \frac{- 17 + 17 ln ( tan ( 7 t ) + sec ( 7 t ) ) sin ( 7 t )}{49}

y = c_{1} cos (7 t) + c_{2} sin (7 t) + \frac{- 17 + 17 ln ( tan ( 7 t ) + sec ( 7 t ) ) sin ( 7 t )}{49}

(\frac{1}{2}) y^{^{''}} + y^{^{'}} + 5 y = sin (3 t)

y^{^{''''}} + 25 y^{^{''}} = sin (5 t) + t e^{6 t} + 4

6 y^{^{''}} - 10 y^{^{'}} - 4 y = x + 2

y^{^{''}} - 2 y^{^{'}} + y = x e^{x} + e^{- x}

y^{^{''}} - y^{^{'}} = x e [x], y (0) = 2, y^{^{'}} (0) = 1