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Beliebt Rechnen >

y^{''}-2y^'+5y=1+t

Lösung

y^{^{''}} - 2 y^{^{'}} + 5 y = 1 + t

Lösung

y = e^{t} (c_{1} cos (2 t) + c_{2} sin (2 t)) + \frac{t}{5} + \frac{7}{25}

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 5 y = 1 + t

Solve linear ODE:

y = e^{t} (c_{1} cos (2 t) + c_{2} sin (2 t)) + \frac{t}{5} + \frac{7}{25}

y = e^{t} (c_{1} cos (2 t) + c_{2} sin (2 t)) + \frac{t}{5} + \frac{7}{25}

Graph

Beliebte Beispiele

y^{''}+y^'=cos(2t)

y^{^{''}} + y^{^{'}} = cos (2 t)

y^{''}+16y=8e^{4t}+8sin(2t)

y^{^{''}} + 16 y = 8 e^{4 t} + 8 sin (2 t)

y^{''}-6y^'+15y=2sin(3t)

y^{^{''}} - 6 y^{^{'}} + 15 y = 2 sin (3 t)

y^{''}-3y^'+2y=1,y^'(4)=3

y^{^{''}} - 3 y^{^{'}} + 2 y = 1, y^{^{'}} (4) = 3

y^{''}+2y^'-3y=e^{-x}(-4x+3)

y^{^{''}} + 2 y^{^{'}} - 3 y = e^{- x} (- 4 x + 3)