(D^2+4)y=cos(2x)

Lösung

(D^{2} + 4) y = cos (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{x sin ( 2 x )}{4}

Schritte zur Lösung

(D^{2} + 4) y = cos (2 x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{x sin ( 2 x )}{4}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{x sin ( 2 x )}{4}

y^{^{''}} + 2 y^{^{'}} + 5 y = 8 cos (x)

y^{^{''}} + 2 y^{^{'}} - 3 y = 1 + x e^{x}

4 y^{^{''}} + y = cos (x)

4 y^{^{''}} - y = e^{\frac{x}{2}} + 5

y^{^{''}} - y^{^{'}} = 2 x e^{x}