(dy)/(dx)= y/(x^2-4)

Lösung

\frac{d y}{d x} = \frac{y}{x ^{2} - 4}

y = e^{- \frac{1}{4} (l n (\frac{x}{2} + 1) - l n (\frac{x}{2} - 1)) + c_{1}}

Schritte zur Lösung

\frac{d y}{d x} = \frac{y}{x ^{2} - 4}

Solve separable ODE:

y = e^{- \frac{1}{4} (l n (\frac{x}{2} + 1) - l n (\frac{x}{2} - 1)) + c_{1}}

y = e^{- \frac{1}{4} (l n (\frac{x}{2} + 1) - l n (\frac{x}{2} - 1)) + c_{1}}

\frac{d v}{d t} = 9.56 - 0.1 v

y^{^{'}} = \frac{y}{x ^{2} - 4}

d y y^{- 2} = \frac{d x}{- x ^{2} + 144}

y = y^{^{'}} x

\frac{d y}{d x} = x^{5} (y - 5), y (0) = 8