(x^2+4)y^'+xy=9x

Lösung

(x^{2} + 4) y^{^{'}} + x y = 9 x

y = \frac{c _{1}}{x ^{2} + 4} + 9

Schritte zur Lösung

(x^{2} + 4) y^{'} (x) + x y = 9 x

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} + 4} + 9

y = \frac{c _{1}}{x ^{2} + 4} + 9

y (1 + x^{3}) y^{^{'}} + x^{2} (1 + y^{2}) = 0

\frac{x ( d y )}{( d x ) - 4 y} = 2 x^{(5)} e^{(x)}

\frac{d x}{x} = - v^{2} d v

\frac{d h}{d t} = - \frac{5}{6 h ^{\frac{3}{2}}}

y^{^{'}} - 4 y = 8