y^'-2y=y

Lösung

y^{^{'}} - 2 y = y

y = e^{3 t + c_{1}}

Schritte zur Lösung

y^{'} (t) - 2 y = y

Solve separable ODE:

y = e^{3 t + c_{1}}

y = e^{3 t + c_{1}}

y^{^{'}} - 2 y = g

\frac{d}{d x} (2 y ln (y)) = \frac{d x}{d x}

\frac{d y}{d x} = x^{2} y^{5}

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 3}{θ cos ( θ )}

y^{^{'}} = t y^{\frac{1}{2}}, y (0) = 0