(xy)(dy)/(dx)=1+y^2

Lösung

(x y) \frac{d y}{d x} = 1 + y^{2}

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

Schritte zur Lösung

(x y) \frac{d y}{d x} = 1 + y^{2}

Solve separable ODE:

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

y^{^{'}} = e^{t + y}, y (ln (2)) = 1

\frac{d y}{d x} x^{2} y - y^{2} = 8

(y ln (x - 2)) y d x = x d y

y^{^{'}} = 6 y^{- 4}, y (0) = 5

\frac{d y}{d x} = \frac{( 2 x ^{2} )}{y ^{2}}