y^'=y^2-3y+2

Lösung

y^{^{'}} = y^{2} - 3 y + 2

y = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}} + \frac{2}{1 - e ^{t + c_{1}}}

Schritte zur Lösung

y^{'} (t) = y^{2} - 3 y + 2

Solve separable ODE:

y = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}} + \frac{2}{1 - e ^{t + c_{1}}}

y = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}} + \frac{2}{1 - e ^{t + c_{1}}}

\frac{d y}{d x} y = 6 u - 5, u = (\frac{1}{3}) x^{7}

y^{^{'}} = 1 + y^{2}, y (0) = 1

(1 + x^{2}) d y + 2 x y d x = 0

3 y^{^{'}} = y

y^{^{'}} = \frac{y}{1 - x ^{2}}