(y^2+3)dx=ysec^2(x)dy

Lösung

(y^{2} + 3) d x = y sec^{2} (x) d y

y = e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 3, y = - e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 3

Schritte zur Lösung

(y^{2} + 3) d x = y sec^{2} (x) d y

Solve separable ODE:

y = e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 3, y = - e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 3

y = e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 3, y = - e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 3

(x^{3} + x^{3}) d x = x y^{2} d y

y^{^{'}} - a \cdot e^{- b \cdot y} = 0

\frac{d v}{d t} = 1 - 3 v

\frac{d y}{d x} = \frac{( 15 x ^{2} - 6 x + 2 )}{( ( y + 2 ) )}

y^{^{'}} = 1 + 2 y