3y^'-y=0

Lösung

3 y^{^{'}} - y = 0

y = e^{\frac{t + c _{1}}{3}}

Schritte zur Lösung

3 y^{'} (t) - y = 0

Solve separable ODE:

y = e^{\frac{t + c _{1}}{3}}

y = e^{\frac{t + c _{1}}{3}}

y^{^{'}} + cos (t) y = cos (t)

\frac{d y}{d x} = \frac{x}{2 y x + y}

y^{^{'}} = \frac{2 x + x y ^{2}}{4 y + x ^{2} y}

y^{^{'}} = 5 y - 4

y^{^{'}} = 5 y - 3