y^'=y^2(9x+5)

Lösung

y^{^{'}} = y^{2} (9 x + 5)

y = - \frac{2}{9 x ^{2} + 10 x + c _{1}}

Schritte zur Lösung

y^{'} (x) = y^{2} (9 x + 5)

Solve separable ODE:

y = - \frac{2}{9 x ^{2} + 10 x + c _{1}}

y = - \frac{2}{9 x ^{2} + 10 x + c _{1}}

y^{^{'}} sec (x) = 5 y^{2}, y (\frac{π}{2}) = \frac{1}{2}

\frac{d Q}{d t} + \frac{Q}{20} = 0

v \frac{d v}{d x} = 2 + x

\frac{d y}{d x} x y + 2 x + 3 x^{2} = 4

3 y^{^{'}} - 4 y - 91 = 2 y^{^{'}}