y^'=(1+x)/(xy),y(1)=-4

Lösung

y^{^{'}} = \frac{1 + x}{x y}, y (1) = - 4

y = - 2 ln (x) + 2 x + 14

Schritte zur Lösung

y^{'} (x) = \frac{1 + x}{x y}

Solve separable ODE:

y = - 2 ln (x) + 2 x + 14

y = - 2 ln (x) + 2 x + 14

\frac{d v}{d t} = 0.4 v + 1000

\frac{d y}{y} = - \frac{d x}{x}

y^{^{'}} = \frac{4 \cdot y}{x} - \frac{4}{x}

y^{^{'}} = - \frac{y ^{2}}{x}

y^{^{'}} + 4 y = 3, 2 x y (0) = 2