xy^'-(7x+1)y=0

Lösung

x y^{^{'}} - (7 x + 1) y = 0

y = e^{7 x + c_{1}} x

Schritte zur Lösung

x y^{'} (x) - (7 x + 1) y = 0

Solve separable ODE:

y = e^{7 x + c_{1}} x

y = e^{7 x + c_{1}} x

csc (θ) d r (θ) = r (θ)^{2} d θ

\frac{d x}{x} - \frac{d y}{y} = 0

\frac{d h}{d t} = 5 h - h^{2}

d y - y d x = 0

(y + x^{2} y) d y = (x y^{2} - x) d x