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Beliebt Rechnen >

y^'=((3x^2+4x-4))/(2y-4),y(1)=3

Lösung

y^{^{'}} = \frac{( 3 x ^{2} + 4 x - 4 )}{2 y - 4}, y (1) = 3

Lösung

y = 2 + x^{3} + 2 x^{2} - 4 x + 2

Schritte zur Lösung

y^{'} (x) = \frac{( 3 x ^{2} + 4 x - 4 )}{2 y - 4}

Solve separable ODE:

y = 2 + x^{3} + 2 x^{2} - 4 x + 2

y = 2 + x^{3} + 2 x^{2} - 4 x + 2

Graph

Beliebte Beispiele

xydy=(1+y^2)dx,y(2)=3

x y d y = (1 + y^{2}) d x, y (2) = 3

y - 3 y^{^{'}} = 1

y^5(dy)/(dx)=3x^3y^6-9x^3

y^{5} \frac{d y}{d x} = 3 x^{3} y^{6} - 9 x^{3}

y^'= 1/(3y^2(x^2+1))

y^{^{'}} = \frac{1}{3 y ^{2} ( x ^{2} + 1 )}

y^'=(3x^2)/(2y-4)

y^{^{'}} = \frac{3 x ^{2}}{2 y - 4}