y=sin(2)(ln(x^2-3x+2))y^'

Lösung

y = sin (2) (ln (x^{2} - 3 x + 2)) y^{^{'}}

y = e^{\int \frac{1}{s i n ( 2 ) l n ( x ^{2} - 3 x + 2 )} d x}

Schritte zur Lösung

y = sin (2) (ln (x^{2} - 3 x + 2)) y^{'} (x)

Solve separable ODE:

y = e^{\int \frac{1}{s i n ( 2 ) l n ( x ^{2} - 3 x + 2 )} d x}

y = e^{\int \frac{1}{s i n ( 2 ) l n ( x ^{2} - 3 x + 2 )} d x}

\frac{d v}{d t} = 90 - \frac{4}{100} v, v = 0, t = 0

y^{^{'}} - 2 y + a = 0

\frac{d x}{d t} = x + c

\frac{d V}{d t} = 20 - 0.2 V

\frac{d y}{d x} + 7 y = y^{2} + 12