y^'=-1/y

Lösung

y^{^{'}} = - \frac{1}{y}

y = - 2 t + c_{1}, y = - - 2 t + c_{1}

Schritte zur Lösung

y^{'} (t) = - \frac{1}{y}

Solve separable ODE:

y = - 2 t + c_{1}, y = - - 2 t + c_{1}

y = - 2 t + c_{1}, y = - - 2 t + c_{1}

[1 + t^{2}] \frac{d y}{d t} = 1 + y^{2}

y^{^{'}} = x^{2} y, y (0) = 1

y^{3} y^{^{'}} + 4 x y^{4} = 8 x

2 x y^{3} + 3 x^{2} y^{2} \frac{d y}{d x} = 0

(t^{3} - 12 t + 27) \frac{d y}{d t} = y