(dh)/(dt)=1-0.5h

Lösung

\frac{d h}{d t} = 1 - 0.5 h

h = - 2 e^{\frac{- t - c _{1}}{2}} + 2

Schritte zur Lösung

\frac{d h}{d t} = 1 - 0.5 h

Solve separable ODE:

h = - 2 e^{\frac{- t - c _{1}}{2}} + 2

h = - 2 e^{\frac{- t - c _{1}}{2}} + 2

\frac{( x ^{2} - 9 )}{x} \frac{d y}{d x} + y = 0, y (5) = 1

y^{^{'}} + 5 x y = \frac{x}{2} - x y

\frac{d y}{d t} = 0.4 y

y^{^{'}} = \frac{( e ^{2 x + y} )}{y}

(5 + x) y^{^{'}} = 2 y