y^'+y=10

Lösung

y^{^{'}} + y = 10

y = - e^{- t - c_{1}} + 10

Schritte zur Lösung

y^{'} (t) + y = 10

Solve separable ODE:

y = - e^{- t - c_{1}} + 10

y = - e^{- t - c_{1}} + 10

y^{^{'}} = 1 - y^{2}, y (0) = 0

y^{^{'}} = x y - 4 x, y (0) = 5

f^{^{'}} (x) + f (x) = 0

\frac{d y}{d x} = y^{2} e^{x} sin (9 x), y (0) = 1

(1 + x^{2}) y^{^{'}} = y - 2