P^'=0.2P

Lösung

P^{^{'}} = 0.2 P

P (t) = e^{0.2 t + c_{1}}

Schritte zur Lösung

P^{'} (t) = 0.2 P (t)

Solve separable ODE:

P (t) = e^{0.2 t + c_{1}}

P (t) = e^{0.2 t + c_{1}}

x^{^{'}} = k x

\frac{d x}{d y} y = 9 x^{2}

(1 + x^{2}) y^{^{'}} + 2 x y = x

y^{^{'}} tan (x) = 9 a + y, y (\frac{π}{3}) = 9 a

x cos (y) \frac{d y}{d x} - sin (y) = 0