(1+e^x)y*y^'=e^y

Lösung

(1 + e^{x}) y \cdot y^{^{'}} = e^{y}

y = - W (\frac{- ln ( 1 + e ^{x} ) + x + c _{1}}{e}) - 1

Schritte zur Lösung

(1 + e^{x}) y \cdot y^{'} (x) = e^{y}

Solve separable ODE:

y = - W (\frac{- ln ( 1 + e ^{x} ) + x + c _{1}}{e}) - 1

y = - W (\frac{- ln ( 1 + e ^{x} ) + x + c _{1}}{e}) - 1

x y^{^{'}} - y = 0, y (0) = x

y^{^{'}} - y = 0, y (0) = 2

\frac{d y}{d t} = 0.04 - \frac{y}{( \frac{4320}{7} )}

y^{^{'}} = \frac{2 x y - 2 x}{x ^{2} + 3}

7 y^{^{'}} - 2 y - 80 = 6 y^{^{'}}