y^4y^'-3y^5=0

Lösung

y^{4} y^{^{'}} - 3 y^{5} = 0

y = e^{3 t + c_{1}}

Schritte zur Lösung

y^{4} y^{'} (t) - 3 y^{5} = 0

Solve separable ODE:

y = e^{3 t + c_{1}}

y = e^{3 t + c_{1}}

\frac{d x}{d t} = 8 x t^{3}

y^{^{'}} = \frac{t y ^{2}}{t ^{2} + 1}, y (0) = 1

d x + y^{2} d y = 0

y e^{y} d y = - x d x

\frac{d x}{d t} = (t e^{x + t})